36^2+b^2=45^2

Solution for 36^2+b^2=45^2 equation:

36^2+b^2=45^2

We move all terms to the left:

36^2+b^2-(45^2)=0

We add all the numbers together, and all the variables

b^2-729=0

a = 1; b = 0; c = -729;
Δ = b2-4ac
Δ = 02-4·1·(-729)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*1}=\frac{-54}{2}
=-27
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*1}=\frac{54}{2}
=27
$